Question

An object with a mass of `6 kg` is revolving around a point at a distance of `8 m`. If the object is making revolutions at a frequency of `6 Hz`, what is the centripetal force acting on the object?

Answer 1

The force acting on the object is `6912pi^2` Newtons.

Explanation:

We'll start by determining the velocity of the object. Since it is revolving in a circle of radius 8m 6 times per second, we know that:

`v = 2pir*6`

Plugging in values gives us:

`v = 96 pi` m/s

Now we can use the standard equation for centripetal acceleration:

`a = v^2/r`
`a = (96pi)^2/8`
`a = 1152pi^2` m/s^2

And to finish the problem we simply use the given mass to determine the force needed to produce this acceleration:
`F = ma`
`F = 6*1152pi^2`
`F = 6912pi^2` Newtons