An object with a mass of #7 kg# is hanging from a spring with a constant of #3 (kg)/s^2#. If the spring is stretched by # 12 m#, what is the net force on the object?

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Answer 1 · 2017-03-08T19:34:47

The net force is #=32.6N# acting downwards

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Let's resolve in the vertical direction #uarr^+#

#F_1=kx=3*12=36N#

#F_2=-mg=-7g=-68.6N#

The net force is

#F=F_1+F_2=36-68.6=-32.6N#

The force is acting downwards,