Question

An object with a mass of `8 kg` is revolving around a point at a distance of `1 m`. If the object is making revolutions at a frequency of `12 Hz`, what is the centripetal force acting on the object?

Answer 1

`F=4*m*pi^2*f^2*r`

Explanation:

we have `F=mv^2/r=momega^2r`
`f=1/T=omega/(2pi)`
`so`
`F=4pi^2mf^2r`