Beremberas saved twice as much as Blata. Shimbash saved $60 more than Blata. If they saved $600 altogether, how much did Shimbash save?

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Answer 1 · 2018-07-15T10:47:47

$$195$

Let $x$ be the amount that Blata saved
Then $2x$ is the amount Beremberas saved
And $x+60$ be the amount Shimbash saved

If they saved $600$ altogether, then the equation would look like below:
$x+2x+x+60=600$
$4x+60=600$
$4x=540$
$x=135$

Therefore, Shimbash saved $135+60=195$

Answer 2 · 2018-07-15T10:57:28

Shimbash saved $$195$

Let us assume, savings of Blata be $$x$ , then the savings of

Berembaras as $$2 x$ and savings of Shimbash as $$(x+60)$ .

By given information , $x+2 x+(x+60)=600$ or

$4 x +60=600 :. 4 x =600-60 or 4 x = 540 or x= 135$

$:. 2 x = 2*135=270 and x+60 = 135+60 =195$

Blata saved $$135$ , Berembaras saved $$270$ and

Shimbash saved $$195$ [Ans]