Between what two consecutive integers does $\sqrt{21}$ $sqrt21$ lie?

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Answer 1 · 2018-04-01T19:15:16

$\sqrt{21}$ $sqrt21$ lies between $4 and 5$ $4 and 5$

We know that,

$\sqrt{16} < \sqrt{21} < \sqrt{25}$ $color(red)(sqrt16 )< sqrt21 < color(red)( sqrt25)$

$\Rightarrow 4 < \sqrt{21} < 5$ $=>color(red)(4 ) < sqrt21 < color(red)( 5)$

Hence $\sqrt{21}$ $sqrt21$ lies between $4 and 5$ $4 and 5$

Answer 2 · 2018-04-01T19:22:41

$5^{2} = 25 and 4^{2} = 16 so \sqrt{21} is between 4 and 5$ $5^2=25 and 4^2=16" so "sqrt21" is between "4 and 5$

Between what two consecutive integers does sqrt21√21sqrt21 lie?