Between which two consecutive integers is the square root of 40?

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Answer 1 · 2018-03-02T11:39:31

$6 < sqrt40 < 7$

The first few square numbers are: $1,4,9,16,25,36,49,$

$sqrt1 =1$

$sqrt4 =2$

$sqrt9=3$

$sqrt16=4$

$sqrt25=5$

$sqrt36=6$
$color(white)(wwwwww)larr sqrt40" "$ lies here
$sqrt49 = 7$

Therefore $sqrt40$ is between $6 and 7$