Consider the line #y=8x-2#. What is the equation of the line that is parallel to this line and passes through the point (-5,6)?

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Answer 1 · 2015-11-26T16:36:22

#y=8x+46#

All lines with the same slope are parallel to each other.

All lines with a slope #8# have equation
#y=8x+C#
where #C# is some constant.

Let's find a constant #C# such that point #(-5,6)# lies on a line:
#6 = 8(-5)+C#
from which follows:
#C = 46#

Therefore, line #y=8x+46# is parallel to a given line #y=8x-2# and passes through point #(-5,6)#.