Differentiate? F(y)=(1y2−5y4)(y+7y3)

1 Answer
Douglas K.
May 12, 2017

dF(y)dy=(−2y−3+20y−5)(y+7y3)+(1y2−5y4)(1+21y2)

Explanation:

Use the product rule:

dF(y)dy=d(1y2−5y4)dy(y+7y3)+(1y2−5y4)d(y+7y3)dy

Do the first derivative:

d(1y2−5y4)dy=d(y−2−5y−4)dy=−2y−3+20y−5

Substitute back into the product rule:

dF(y)dy=(−2y−3+20y−5)(y+7y3)+(1y2−5y4)d(y+7y3)dy

Do the second derivative:

d(y+7y3)dy=1+21y2

Substitute back into the product rule:

dF(y)dy=(−2y−3+20y−5)(y+7y3)+(1y2−5y4)(1+21y2)

Related questions
See all questions in Product Rule
Impact of this question
9279 views around the world
You can reuse this answer
Creative Commons License