Evaluate $""^3C_1$ ?

Question

3
2
6
1

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Answer 1 · 2017-04-05T05:08:17

$C_(3,1)=(3!)/((1!)(3-1)!)=(3!)/(2!)=6/2=3$

I write combinations as:

$C_(n,k)=(n!)/((k!)(n-k)!)$ with $n="population", k="picks"$

and so

$C_(3,1)=(3!)/((1!)(3-1)!)=(3!)/(2!)=6/2=3$

I don't understand the additional numbers in the explanatory text box - but I hope the above will clarify what you are looking to calculate.