Evaluate #""^3C_1# ?

Question

3
2
6
1

3876 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-04-05T05:08:17

#C_(3,1)=(3!)/((1!)(3-1)!)=(3!)/(2!)=6/2=3#

I write combinations as:

#C_(n,k)=(n!)/((k!)(n-k)!)# with #n="population", k="picks"#

and so

#C_(3,1)=(3!)/((1!)(3-1)!)=(3!)/(2!)=6/2=3#

I don't understand the additional numbers in the explanatory text box - but I hope the above will clarify what you are looking to calculate.