Find the formula weight of $Ca {(C_{6} H_{12} {NO}_{3} S)}_{2}$ $"Ca"("C"_6"H"_12"NO"_3"S")_2$ ?

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Answer 1 · 2017-07-13T10:18:05

$396$ $396$

$C a = 40$ $Ca = 40$

$C = 12$ $C = 12$

$H = 1$ $H = 1$

$N = 14$ $N = 14$

$S = 32$ $S = 32$

$O = 16$ $O = 16$

So

$= 40 + [(12 \times 6) + (1 \times 12) + 14 + 32 + (16 \times 3)] \times 2$ $= 40 + [(12 xx 6) + (1 xx 12) + 14 + 32 + (16 xx 3)] xx 2$

$= 40 + [72 + 12 + 14 + 32 + 48] \times 2$ $= 40 + [72 + 12 + 14 + 32 + 48] xx 2$

$= 40 + 178 \times 2$ $= 40 + 178 xx 2$

$= 396$ $= 396$

Find the formula weight of "Ca"("C"_6"H"_12"NO"_3"S")_2Ca(C6H12NO3S)2"Ca"("C"_6"H"_12"NO"_3"S")_2?