Question

Given `sectheta=5` and `tantheta=2sqrt6`, how do you find `sintheta`?

Answer 1

I found: `sintheta=2/5sqrt(6)`

Explanation:

We can write:
`sectheta=1/(costheta)=5`
`tantheta=(sintheta)/(costheta)=2sqrt(6)`

From the first:
`costheta=1/5`
Into the second:
`(sintheta)/(1/5)=2sqrt(6)`
And so:
`sintheta=2/5sqrt(6)`