Glucose is used as an energy source by the human body. The overall reaction in the body is described by the equation C6H12O6(aq) + 6O2(g) = 6CO2(g) + 6H2O(l). How many grams of oxygen are required to convert 28.0 g of glucose to CO2 and H2O?

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Answer 1 · 2017-10-15T00:05:58

28.1 grams to three significant figures.

Glucose #C_6H_12O_6# has a molecular mass of 180 grams.

# 6 xx C = 6 xx 12 = 72#
# 12 xx H = 12 xx 1 = 12#
# 6 xx O = 6 xx 16 =96# adding these gives
180 grams per mole.

To find the number of moles divide 28.0 grams by 180. grams

# 28.0/180 = .156 #moles

It requires 6 moles of Oxygen to "burn" 1 mole of glucose. so to find the number of moles of Oxygen required multiply by 6

# .156 xx 6 = .936# moles of Oxygen required.

Oxygen has a molecular mass of 32

# 2 xx O = 2 xx 16 = 32 # grams per mole.

To find the number of grams of Oxygen multiple moles by grams per mole.

# .936 xx 32 = 28.1 # grams Oxygen