HHow do I integrate f(x)= x^2 e^(-5x) by parts?

1 Answer
Gió
Jan 28, 2015

Here you have to integrate by parts twice to "kill" your x^2.
You start with the first "by parts" as:
intx^2e^(-5x)dx=x^2*e^(-5x)/(-5)-inte^(-5x)/(-5)*2xdx=
Which can be written as:
=x^2*e^(-5x)/(-5)+1/5inte^(-5x)*2xdx=
Now you go for another integration by parts and get:
=x^2*e^(-5x)/(-5)+1/5[e^(-5x)/(-5)*2x-inte^(-5x)/(-5)*2dx]=
=x^2*e^(-5x)/(-5)+1/5[e^(-5x)/(-5)*2x+2/5inte^(-5x)dx]=
=x^2*e^(-5x)/(-5)+1/5e^(-5x)/(-5)*2x+1/5*2/5e^(-5x)/(-5)=

=e^(-5x)[-x^2/5-(2x)/25-2/125]+c

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