Question

How can you use trigonometric functions to simplify `2 e^( ( 13 pi)/12 i )` into a non-exponential complex number?

Answer 1

Use `Ae^(thetai) = Acos(theta) + Asin(theta)i`

Explanation:

`Ae^(thetai) = Acos(theta) + Asin(theta)i`

`2e^((13pi)/12i) = 2cos((13pi)/12) + 2sin((13pi)/12)i`

I used a calculator to compute the real and imaginary parts, they are not nice round numbers so I decided to leave you with this form.