How do find the quotient of (2x^3 − 3x 2 + x − 6) ÷ (x − 4)(2x33x2+x6)÷(x4)?

How do find the quotient of (2x^3 − 3x^2 + x − 6) ÷ (x − 4)(2x33x2+x6)÷(x4)?

1 Answer
Aug 11, 2018

The quotient polynomial :
q(x)=2x^2+5x+21 and"the Remainder"=78q(x)=2x2+5x+21andthe Remainder=78

Explanation:

(2x^3-3x^2+x-6)div(x-4)(2x33x2+x6)÷(x4)

Using synthetic division :

We have , p(x)=(2x^3-3x^2+x-6) and "divisor : " x=4p(x)=(2x33x2+x6)anddivisor : x=4

We take ,coefficients of p(x) to 2,-3,1,-6p(x)2,3,1,6

. 4 |4 2color(white)(....)-3color(white)(.......)1color(white)(.......)-6
ulcolor(white)(...)| ul(0color(white)( .........)8color(white)(.......)20color(white)(.........)84
color(white)(....)2color(white)(........)5color(white)(.......)21color(white)(......)color(violet)(ul|78|
We can see that , quotient polynomial :

q(x)=2x^2+5x+21 and"the Remainder"=78

Hence ,

(2x^3-3x^2+x-6)=(x-4)(2x^2+5x+21 )+(78)