How do I evaluate $int(13 x^2 + 12 x^-2)dx$ ?

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Answer 1 · 2015-01-27T20:32:33

I would use the integral of a sum

$intf(x)+g(x)dx=intf(x)dx+intg(x)dx$

to divide the argument of the igral giving:

$int13x^2dx+int12x^-2dx=$

and integrating:

$(13x^(2+1))/(2+1)+(12x^(-2+1))/(-2+1)=13/3x^3-12/x+c$

How do I evaluate int(13 x^2 + 12 x^-2)dxint(13 x^2 + 12 x^-2)dx?