Question

How do I evaluate the integral `intln(2x)/ x^2 dx`?

Answer 1

I would use integration by parts and the fact that:
`1/x^2=x^-2`;
derivative of `ln(2x)` is: `2/(2x)=1/x` (Chain Rule);
and `intx^ndx=x^(n+1)/(n+1)+c`

You get: