How do I factor; x^2-15x+56=?

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Answer 1 · 2018-03-05T01:37:56

$x^2-7x-8x+56=?$

For $x^2-15x+56$

it is gonna be like this:

$x^2-7x-8x+56$

$=x(x-7)-8(x-7)$

$=(x-7)(x-8)$

Then if

$x^2-15x+56 = 0$

$(x-7)(x-8)= 0$

So

$x-7=0 => x=7$

$x-8=0 => x=8$