How do I find all real and complex zeros of #x^2+1#?

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Answer 1 · 2014-09-25T21:04:06

You find the zeros by setting the expression equal to zero.

#x^2+1=0#

Then solve for #x#

#x^2=-1#

#sqrt(x^2)=+-sqrt(-1)#

#x=+-i#

This expression has 2 imaginary roots #+i# and #-i#.