How do I find the 6th term of the geometric sequence for which $t_{3} = 444$ $t_3 = 444$ and $t_{7} = 7104$ $t_7 = 7104$ ?

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How do I find the 6th term of the geometric sequence for which $t_{3} = 444$ $t_3 = 444$ and $t_{7} = 7104$ $t_7 = 7104$ ?

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Answer 1 · 2015-05-11T14:13:53

$t_{6} = 3552$ $t_6=3552$

First you have to calculate $r$ $r$ . To do so you can use the formula

$t_{7} = t_{3} \cdot r^{4}$ $t_7=t_3*r^4$ , so $r = \sqrt[4]{\frac{t_{7}}{t_{4}}} = 2$ $r= root(4)((t_7)/(t_4))=2$ . Now you can calculate $t_{6} = \frac{t_{7}}{r} = \frac{7104}{2} = 3552$ $t_6=t_7/r=7104/2=3552$

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How do I find the 6th term of the geometric sequence for which $t_{3} = 444$ $t_3 = 444$ and $t_{7} = 7104$ $t_7 = 7104$ ?

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How do I find the 6th term of the geometric sequence for which t_3 = 444t3=444t_3 = 444 and t_7 = 7104t7=7104t_7 = 7104?

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How do I find the 6th term of the geometric sequence for which $t_{3} = 444$ $t_3 = 444$ and $t_{7} = 7104$ $t_7 = 7104$ ?