How do I find the center of an ellipse in standard form?

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Answer 1 · 2014-10-19T02:40:35

An ellipse in standard form looks like

#(x - h)^2/a^2 + (y - k)^2/b^2 = 1#

or

#(x - h)^2/b^2 + (y - k)^2/a^2 = 1#

where #a >= b#.
However, for your question, we don't need to be concerned with #a# and #b#

An ellipse in standard form is centered at (h, k).

For example,

#(x - 1)^2/1 + (y + 2)^2/4 = 1# is centered at (1, -2)

#x^2/16 + (y - 5)^2/9 = 1# is centered at (0, 5)