How do I find the exponential function of the form $f(x)=ab^x$ for which $f(-1)=10$ and $f(0)=5$ ?

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Answer 1 · 2015-01-30T21:33:38

The answer is: $y=5(1/2)^x$

$f(-1)=10rArr10=ab^-1rArr10=a/brArra=10b$

$f(0)=5rArr5=ab^0rArr5=a*1rArra=5$ .

So:
$a=5andb=1/2$ .

The function is: $y=5(1/2)^x$ .

How do I find the exponential function of the form f(x)=ab^xf(x)=ab^x for which f(-1)=10f(-1)=10 and f(0)=5f(0)=5?