How do I find the polar form of $a+bi$ ?

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Answer 1 · 2015-05-10T16:59:13

I presume we're looking for a radius $r$ and angle $theta$ such that $a + bi = r(cos theta + i sin theta)$ .

Pythagoras theorem gives us $r = sqrt(a^2+b^2)$ .

Simple trigonometry gives us $tan theta = b/a$ , so $theta = arctan (b/a)$ .

How do I find the polar form of a+bia+bi?