How do I find the value of sin (pi/12)?

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How do I find the value of sin (pi/12)?

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Answer 1 · 2015-09-15T14:21:05

$sin (\frac{π}{12}) = \frac{\sqrt{2}}{4} \cdot (\sqrt{3} - 1)$ $sin(pi/12)=sqrt2/4*(sqrt3-1)$

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$sin (\frac{π}{12}) = sin (\frac{π}{3} - \frac{π}{4}) = sin (\frac{π}{3}) \cdot cos (\frac{π}{4}) - cos (\frac{π}{3}) \cdot sin (\frac{π}{4}) \Rightarrow sin (\frac{π}{12}) = \frac{\sqrt{3}}{2} \cdot \frac{\sqrt{2}}{2} - \frac{1}{2} \cdot \frac{\sqrt{2}}{2} = \frac{\sqrt{2}}{4} \cdot (\sqrt{3} - 1)$ $sin(pi/12)=sin(pi/3-pi/4)=sin(pi/3)*cos(pi/4)-cos(pi/3)*sin(pi/4)=>sin(pi/12)=sqrt3/2*sqrt2/2-1/2*sqrt2/2=sqrt2/4*(sqrt3-1)$

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How do I find the value of sin (pi/12)?

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