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How do I find the value of tan 6π?

1 Answer

Apr 11, 2018

$tan (6 π) = tan (π) = 0$ $tan(6pi)=tan(pi)=0$

Explanation:

Tangent has a period of $π,$ $pi,$ meaning $tan (a) = tan (a + n π)$ $tan(a)=tan(a+npi)$ where $n$ $n$ is any positive or negative integer.

So,

$tan (6 π) = tan (6 π - 5 π) = tan (π) = 0$ $tan(6pi)=tan(6pi-5pi)=tan(pi)=0$

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