How do I put 73 in simplest radical form?

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Answer 1 · 2015-04-15T18:05:49

Look for perfect squares that divide into 73:

The first few perfect squares are :

$2^2=4$ Does not go into $73$ without remainder

$3^2=9$ Does not go into $73$ without remainder

$4^2=16$ is even, we already checked 4 doesn't go in evenly

$5^2 = 25$ Does not go into $73$ without remainder

$6^2$ is even

$7^2=49$

$9^2 = 81$ is greater than $73$

$73$ is not divisible by a perfect square, so $sqrt73$ cannot be simplified.