Question

How do I use substitution to find the solution of the system of equations `c+3d=8` and `c=4d-6`?

Answer 1

equations provided are:
`c + 3d =8` .................`(1)`
`c = 4d - 6` ..........`(2)`

Substituting equation `(2)` in equation `(1)`
`c + 3d = (4d - 6) + 3d = 8`
`7d - 6 = 8`
`7d = 14`
`d= 2`

Substituting the value of `d` to find `c`
`c = 4d - 6 = 4xx(2) -6 = 8-6 =2`

the solution for the equations are `c =2 , d=2`