How do I use the quadratic formula to solve #f(x) = x^2 + 3x - 7#?

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Answer 1 · 2014-09-30T03:49:03

#ax^2+bx+c=0#

#x^2+3x-7=0#

#a=1, b=3, c=-7#

Quadratic formula

#x=(-b+-sqrt(b^2-4ac))/(2a)#

#x=(-(3)+-sqrt((3)^2-4(1)(-7)))/(2(1))#

#x=(-3+-sqrt(9+28))/2#

#x=(-3+-sqrt(37))/2#