How do I use the the binomial theorem to expand (t + w)^4(t+w)4?

1 Answer
Sep 28, 2015

(t+w)^4=t^4+4t^3w^1+6t^2w^2+4t^1w^3+w^4(t+w)4=t4+4t3w1+6t2w2+4t1w3+w4

Explanation:

First, you should get to know Pascal's triangle. Here's a small portion of it up to 6 lines. Basically you're just adding the numbers that are beside each other, then writing the sum below them. (For example, 1+21+2 in the third line equals to 33 in the fourth line.) If you want a better explanation for that, feel free to do some more research on it.
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Okay, so take a look at the triangle. The numbers in each line are the coefficients of the terms when a binomial is raised to a certain power. The first line is for n^0n0, the second is for n^1n1, the third is for n^2n2, etc.

For (t+w)^4(t+w)4, we'll use the 5th line (1 4 6 4 1). Let's write it down:
1tw+4tw+6tw+4tw+1tw1tw+4tw+6tw+4tw+1tw.

Now, for the first term, the exponent of the first variable tt will be 44 and it will descend in the next terms. The exponent of ww will start at 00 and ascend in the next terms.
1t^4w^0+4t^3w^1+6t^2w^2+4t^1w^3+1t^0w^41t4w0+4t3w1+6t2w2+4t1w3+1t0w4

Simplify:
t^4+4t^3w^1+6t^2w^2+4t^1w^3+w^4t4+4t3w1+6t2w2+4t1w3+w4