How do you add 3\frac { 7} { 10} + 4\frac { 1} { 15} + 2\frac { 2} { 13}?

2 Answers

9\frac { 359} { 390}

Explanation:

Okay, so first you put all the fractions into a Common Denominator what this means is that all the bottom numbers have to be equal.

So let's add the first two numbers first

3\frac { 7} { 10} + 4\frac { 1} { 15}

What is a common denominator for 15 and 10: the answer is 30.

A brief overview of a common denominator: to find the common denominator list the multiples of 15 and 10. For 15 it would be:

15 (15 * 1 = 15)

30 (15 * 2 = 30)

Therefore, we could conclude that since the multiples of 10 are pretty simple.

10 * 1 = 10

10 * 2 = 20

10 * 3= 30

We found a common denominator: 30!

So next we multiply each number the top and the bottom the same so if we multiple 10 by 3 to equal 30; we do the same for the top number so

7 * 3 =21

Same goes for the other number we multiplied 15 by 2 to find 30 and we do the same for the top

1 * 2 = 2

But we don't do anything to the whole number because it's not a part of the fraction! Therefore the numbers are going to look like

3\frac { 21} { 30} + 4\frac { 2} { 30}

Which equals this is all just addition which I shouldn't be explaining

7\frac { 23} { 30

Now we do the next part

7\frac { 23} { 30} + 2\frac { 2} { 13}

A common multiple of 13 and 30 would be 390.

Which sounds like a lot but is just a multiple of 9 for 13 and a multiple of 13 for 30.

So we do the same thing we did above.

9\frac { 359} { 390}

Which cannot be simplified!

Remember always simplify during tests or quizzes if you don't you will definite loose points; which is a frugal way to lose points after all that hard work.

Jan 5, 2017

9color(white)(.) 359/390

Explanation:

Split the numbers so that we have:
(3+4+2)+(7/10+1/15+2/13)

The brackets are only there to highlight the grouping of numbers.

This gives: 9+(7/10+1/15+2/13)

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
color(blue)("Dealing with the fractional group of numbers")

A fractions structure is: ("count")/("size indicator")->("numerator")/("denominator")

You can not directly add the 'counts' (numerators) unless the
'size indicators' (denominators) are all the same.

color(brown)("A sort of cheat method for a common denominator")

color(white)(3)15
ul(color(white)(3)13) larr" Multiply"
150
ul(color(white)(1)45)larr" Add"
195 larr" both 15 and 13 are factors of this number"

The last digit of 195 is 5 so 195 can not have 10 as a whole number factor. So lets try changing the 5 into 0

195
ul(color(white)(19)2) larr" multiply"
390 larr" all of 10, 15 and 13 will divide into this number"
.........................................................................................

390-:10=39
390-:15=26
390-:13=30

color(green)([7/10color(red)(xx1)]color(white)(..)+color(white)(..)[1/15color(red)(xx1)]color(white)(..)+color(white)(..)[2/13color(red)(xx1)]

color(green)([7/10color(red)(xx39/39)]+color(white)(.)[1/15color(red)(xx26/26)]color(white)(.)+color(white)(.)[2/13color(red)(xx30/30)]

color(green)(" "[273/390]" "+" "[26/390]" "+" "[60/390] )

color(white)(.)

color(green)(" "359/390)
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
color(blue)("Putting it all together")

" "color(blue)(9 359/390)