How do you add $(-4+8i)+(1+2i)$ in trigonometric form?

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Answer 1 · 2016-04-20T19:56:26

side by side

You add real parts, you add imaginary parts, independently.
real part: $-4 + 1 = -3$
imaginary part $8 + 2 = 10$

result $-3 + 10i$

How do you add (-4+8i)+(1+2i)(-4+8i)+(1+2i) in trigonometric form?