How do you add $(4 + i) - (- 3 + 2 i)$ $(4 + i) - (-3 + 2i)$ ?

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Answer 1 · 2015-12-13T22:11:17

$7 - i$ $7-i$

Distribute the negative sign in the second term.

$4 + i - (- 3) - (2 i)$ $4+i-(-3)-(2i)$

$4 + i + 3 - 2 i$ $4+i+3-2i$

Combine like terms.

$4 + 3 + i - 2 i$ $4+3+i-2i$

$7 - i$ $7-i$

How do you add (4 + i) - (-3 + 2i) (4+i)−(−3+2i)(4 + i) - (-3 + 2i) ?