How do you add $(49x-2)+(4x^2+x+7)$ ?

Question

1900 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-03-19T01:48:32

$4x^2 + 50x + 5$

Add
$(49x−2)+(4x2+x+7)$

1) Clear the parentheses by distributing the coefficients.

In this case, both parentheses have coefficients of $1$ , which are not written because they are understood.

After you have cleared the parentheses by multiplying all the terms inside each set of parentheses by $1$ , you get this:
$49x - 2 + 4x^2 + x + 7$

2) Group like terms
$4x^2 + 49x + x -2 + 7$

3) Combine like terms
$4x^2 + 50x + 5$ $larr$ answer

How do you add (49x-2)+(4x^2+x+7)(49x-2)+(4x^2+x+7)?