How do you add $(4v^3- 3v^2+ 2v)+ (3v^3+ 6v^2- 9v)$ ?

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Answer 1 · 2016-12-06T21:28:02

$7v^3 + 3v^2 - 7v$

Step 1) to answering this question is to take all of the terms out of parenthesis:

$4v^3 - 3v^2 + 2v + 3v^3 + 6v^2 - 9v$

Next, group like terms:

$4v^3 + 3v^3 - 3v^2 + 6v^2 + 2v - 9v$

Now, add like terms:

$(4 + 3)v^3 + (-3 + 6)v^2 + (2 - 9)v$

$7v^3 + 3v^2 - 7v$

How do you add (4v^3- 3v^2+ 2v)+ (3v^3+ 6v^2- 9v)(4v^3- 3v^2+ 2v)+ (3v^3+ 6v^2- 9v)?