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How do you add $(6 + i) + (7 - 3 i)$ $(6+i)+(7-3i)$ in trigonometric form?

1 Answer

Feb 20, 2017

See below

Explanation:

You don't add them in trig form.

You add them simply as: $(6 + i) + (7 - 3 i) = 13 - 2 i$ $(6+i)+(7-3i) = 13-2 i$

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