How do you add (6-i)(6−i) and (-7+2i)(−7+2i) in trigonometric form?

1 Answer
Leland Adriano Alejandro
Apr 2, 2016

(6-i)+(-7+2i)=(6−i)+(−7+2i)=

Explanation:

First we add algebraically
(6-i)+(-7+2i)=(6-7)+(-1+2)i=-1+i=sqrt((-1)^2+1^2)[cos(arctan(1/-1))+isin(arctan(1/-1))](6−i)+(−7+2i)=(6−7)+(−1+2)i=−1+i=√(−1)2+12[cos(arctan(1−1))+isin(arctan(1−1))]

=sqrt2[cos(arctan(1/-1))+isin(arctan(1/-1))]=√2[cos(arctan(1−1))+isin(arctan(1−1))]

God bless....I hope the explanation is useful.

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