How do you add $(6x^2-x-4) + (2x^2-x-5)$ ?

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Answer 1 · 2018-04-01T20:03:09

$8x^2-2x-9$

The parenthesis are really unnecessary in this problem. We just need to combine our like terms:

The $x^2$ terms with each other, the $x$ terms with each other, and the constants. Doing this, we get:

$8x^2-2x-9$

The key realization when we're doing problems like these is to see if we have like terms, and if we do, combine them.

Hope this helps!

How do you add (6x^2-x-4) + (2x^2-x-5)(6x^2-x-4) + (2x^2-x-5)?