How do you add $(-7+7i)+(6-2i)$ in trigonometric form?

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Answer 1 · 2018-07-15T19:08:34

Hint is given below

HINT:

$-7+7i=7\sqrt2(\cos ({3\pi}/4)+i\sin({3\pi}/4))$

$6-2i=2\sqrt10(\cos (-\tan^{-1}(1/3))+i\sin(-\tan^{-1}(1/3)))$

How do you add (-7+7i)+(6-2i)(-7+7i)+(6-2i) in trigonometric form?