How do you add $(7 b - 5) + (7 b + 5)$ $(7b - 5) + ( 7b + 5)$ ?

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Answer 1 · 2017-06-04T14:52:33

See a solution process below:

First, remove all of the terms from parenthesis. Be careful to handle the signs of each individual term correctly:

$7 b - 5 + 7 b + 5$ $7b - 5 + 7b + 5$

Next, group like terms:

$7 b + 7 b - 5 + 5$ $7b + 7b - 5 + 5$

Now, combine like terms:

$(7 + 7) b + (- 5 + 5)$ $(7 + 7)b + (-5 + 5)$

$14 b + (0)$ $14b + (0)$

$14 b$ $14b$

How do you add (7b - 5) + ( 7b + 5)(7b−5)+(7b+5)(7b - 5) + ( 7b + 5)?