How do you add $8 (1 + 3 f^{2}) + 2 f^{2}$ $8( 1+ 3f ^ { 2} ) + 2f ^ { 2}$ ?

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Answer 1 · 2018-07-12T06:08:31

$8 + 26 f^{2}$ $8 + 26f^2$

Given: $8 (1 + 3 f^{2}) + 2 f^{2}$ $8(1+3f^2) + 2f^2$

Before adding you must distribute:

$8 (1 + 3 f^{2}) + 2 f^{2} = 8 + 24 f^{2} + 2 f^{2}$ $8(1+3f^2) + 2f^2 = 8 + 24f^2 + 2f^2$

Add like-terms:

$= 8 + 26 f^{2}$ $= 8 + 26f^2$

How do you add 8(1+3f2)+2f28( 1+ 3f ^ { 2} ) + 2f ^ { 2}?