How do you add and subtract $3x^2 + 2x - 5$ and $-4 + 7x^2$ ?

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Answer 1 · 2015-06-07T18:59:17

Addition:

$(3x^2+2x-5)+(-4+7x^2)$

$=3x^2+2x-5-4+7x^2$

$=3x^2+7x^2+2x-5-4$

$=(3+7)x^2+2x-9$

$=10x^2+2x-9$

Subtraction:

$(3x^2+2x-5)-(-4+7x^2)$

$=3x^2+2x-5+4-7x^2$

$=3x^2-7x^2+2x-5+4$

$=(3-7)x^2+2x-1$

$=-4x^2+2x-1$

How do you add and subtract 3x^2 + 2x - 53x^2 + 2x - 5 and -4 + 7x^2-4 + 7x^2?