How do you add and subtract the radicals $3 \sqrt{\frac{5}{12}} + \sqrt{\frac{12}{5}} - \frac{1}{3} \sqrt{60}$ $3sqrt(5/12) + sqrt(12/5) -1/3sqrt60$ ?

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How do you add and subtract the radicals $3 \sqrt{\frac{5}{12}} + \sqrt{\frac{12}{5}} - \frac{1}{3} \sqrt{60}$ $3sqrt(5/12) + sqrt(12/5) -1/3sqrt60$ ?

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Answer 1 · 2018-07-26T22:49:21

$\frac{7}{2 \sqrt{15}}$ $7/{2\sqrt15}$

Explanation:

Given that

$3 \sqrt{\frac{5}{12}} + \sqrt{\frac{12}{5}} - \frac{1}{3} \sqrt{60}$ $3\sqrt{5/12}+\sqrt{12/5}-1/3\sqrt{60}$

$= 3 \frac{\sqrt{5}}{\sqrt{12}} + \frac{\sqrt{12}}{\sqrt{5}} - \frac{1}{3} \sqrt{60}$ $=3\sqrt{5}/{\sqrt12}+\sqrt{12}/{\sqrt5}-1/3\sqrt{60}$

$= \frac{3 \cdot 3 (\sqrt{5} \sqrt{5}) + 3 (\sqrt{12} \sqrt{12}) - (\sqrt{60} \sqrt{60})}{3 \sqrt{60}}$ $={3\cdot 3(\sqrt5\sqrt5)+3(\sqrt12\sqrt12)-(\sqrt60\sqrt60)}/{3\sqrt{60}}$

$= \frac{9 (5) + 3 (12) - (60)}{3 \sqrt{60}}$ $={9(5)+3(12)-(60)}/{3\sqrt{60}}$

$= \frac{45 + 36 - 60}{3 \sqrt{60}}$ $={45+36-60}/{3\sqrt{60}}$

$= \frac{21}{3 \sqrt{60}}$ $=21/{3\sqrt60}$

$= \frac{7}{2 \sqrt{15}}$ $=7/{2\sqrt15}$

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How do you add and subtract the radicals $3 \sqrt{\frac{5}{12}} + \sqrt{\frac{12}{5}} - \frac{1}{3} \sqrt{60}$ $3sqrt(5/12) + sqrt(12/5) -1/3sqrt60$ ?

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How do you add and subtract the radicals $3 \sqrt{\frac{5}{12}} + \sqrt{\frac{12}{5}} - \frac{1}{3} \sqrt{60}$ $3sqrt(5/12) + sqrt(12/5) -1/3sqrt60$ ?