How do you add and subtract the radicals 3sqrt(5/12) + sqrt(12/5) -1/3sqrt603512+1251360?

1 Answer

7/{2\sqrt15}7215

Explanation:

Given that

3\sqrt{5/12}+\sqrt{12/5}-1/3\sqrt{60}3512+1251360

=3\sqrt{5}/{\sqrt12}+\sqrt{12}/{\sqrt5}-1/3\sqrt{60}=3512+1251360

={3\cdot 3(\sqrt5\sqrt5)+3(\sqrt12\sqrt12)-(\sqrt60\sqrt60)}/{3\sqrt{60}}=33(55)+3(1212)(6060)360

={9(5)+3(12)-(60)}/{3\sqrt{60}}=9(5)+3(12)(60)360

={45+36-60}/{3\sqrt{60}}=45+3660360

=21/{3\sqrt60}=21360

=7/{2\sqrt15}=7215