How do you add $\sqrt{12} + \sqrt{75}$ $sqrt12+sqrt75$ ?

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Answer 1 · 2015-10-06T13:30:49

If you take the number apart (factorize) you'll see that:
$12 = 2 \cdot 2 \cdot 3 and 75 = 3 \cdot 5 \cdot 5$ $12=2*2*3and75=3*5*5$

You can take the 'doubles' (squares) out from under the root, where they become single:

$\sqrt{12} = \sqrt{2 \cdot 2 \cdot 3} = \sqrt{2^{2}} \cdot \sqrt{3} = 2 \sqrt{3}$ $sqrt12=sqrt(2*2*3)=sqrt(2^2)*sqrt3=2sqrt3$

$\sqrt{75} = \sqrt{5 \cdot 5 \cdot 3} = \sqrt{5^{2}} \cdot \sqrt{3} = 5 \sqrt{3}$ $sqrt75=sqrt(5*5*3)=sqrt(5^2)*sqrt3=5sqrt3$

Adding these will give you $7 \sqrt{3}$ $7sqrt3$ as the final answer.

How do you add sqrt12+sqrt75√12+√75sqrt12+sqrt75?