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How do you add $(x^{3} + 2 x - 1) + (3 x^{2} + 4)$ $( x^3+2x-1)+(3x^2+4)$ ?

1 Answer

Manish Bhardwaj

May 19, 2015

$(x^{3} + 2 x - 1) + (3 x^{2} + 4)$ $( x^3+2x-1)+(3x^2+4)$

$x^{3}$ $x ^3$ + $3 x^{2}$ $3x^2$ + $2 x$ $2x$ -1 + 4

$x^{3}$ $x ^3$ + $3 x^{2}$ $3x^2$ + $2 x$ $2x$ + 3

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