How do you add $(z -8/3) + (4/3z^2 -z +1$ ?

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Answer 1 · 2015-04-29T12:03:50

Only terms containing $z$ to the same exponent can be combined.

$(z-8/3)+(4/3z^2-z+1)$

$color(green)(4/3z^2) + color(red)(z-z) + color(blue)((-8/3)+1)$

$=4/3z^2-5/3$

$=(4z^2-5)/3$

How do you add (z -8/3) + (4/3z^2 -z +1(z -8/3) + (4/3z^2 -z +1?