How do you calculate ${cos}^{- 1} (0.7253)$ $cos^-1(0.7253)$ ?

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How do you calculate ${cos}^{- 1} (0.7253)$ $cos^-1(0.7253)$ ?

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Answer 1 · 2017-02-17T05:19:05

$43^{\circ} 51 + k 360^{\circ}$ $43^@51 + k360^@$
$316^{\circ} 49 + k 360^{\circ}$ $316^@49 + k360^@$

Explanation:

Find arccos (0.7253)
Use calculator and trig unit circle -->
cos x = 0.7253 ---> arc $x = \pm 43^{\circ} 51 + k 360^{\circ}$ $x = +- 43^@51 + k360^@$
Since the arc $- 43^{\circ} 51$ $- 43^@51$ is co-terminal to arc $(360 - 43.51 = 316^{\circ} 49)$ $(360 - 43.51 = 316^@49)$ , there for, the general answers are:
$43^{\circ} 51 + k 360^{\circ}$ $43^@51 + k360^@$
$316^{\circ} 49 + k 360^{\circ}$ $316^@49 + k360^@$

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How do you calculate ${cos}^{- 1} (0.7253)$ $cos^-1(0.7253)$ ?

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How do you calculate cos−1(0.7253)cos^-1(0.7253)?

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How do you calculate ${cos}^{- 1} (0.7253)$ $cos^-1(0.7253)$ ?