How do you calculate ${cot}^{- 1} (- 5)$ $cot^-1(-5)$ ?

Question

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Answer 1 · 2015-11-29T23:02:48

Calculate ${cot}^{- 1} (- 5)$ $cot^-1 (-5)$

Ans: $- 11^{\circ} 31 + k 180$ $-11^@31 + k180$

cot x= 1/(tan x). First, find tan x.
Use calculator -->
tan x = 1/(cot) = -1/5 = -0.2 --> arc $x = - 11^{\circ} 31 . + k 180$ $x = - 11^@31. + k180$

k = 1 --> x = 168.69
k = 2 --> x = 348.69

How do you calculate cot−1(−5)cot^-1(-5)?