How do you calculate the ${cos}^{- 1} (\frac{1}{2})$ $Cos^-1 (1/2)$ ?

Question

How do you calculate the ${cos}^{- 1} (\frac{1}{2})$ $Cos^-1 (1/2)$ ?

1 Answer

Impact of this question

1734 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-03-27T09:22:52

The pricipal value of $θ = {cos}^{- 1} x$ $theta =cos^-1x$ should
$0 \leq θ \leq π$ $0<=theta<=pi$
So ${cos}^{- 1} (\frac{1}{2}) = {cos}^{- 1} (cos (\frac{π}{3})) = \frac{π}{3}$ $cos^-1(1/2)=cos^-1(cos(pi/3))=pi/3$

Science

Math

Humanities

... and beyond

How do you calculate the ${cos}^{- 1} (\frac{1}{2})$ $Cos^-1 (1/2)$ ?

1 Answer

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

How do you calculate the cos−1(12)Cos^-1 (1/2)?

1 Answer

Related questions

Impact of this question

How do you calculate the ${cos}^{- 1} (\frac{1}{2})$ $Cos^-1 (1/2)$ ?