How do you calculate the molarity of a solution prepared by dissolving 95.5 grams of $K N O_{3}$ $KNO_3$ in enough water to make 750 mL of solution?

Question

How do you calculate the molarity of a solution prepared by dissolving 95.5 grams of $K N O_{3}$ $KNO_3$ in enough water to make 750 mL of solution?

1 Answer

Impact of this question

8115 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-05-29T15:47:12

$Molarity = \frac{Moles of solute}{Volume of solution}$ $"Molarity"="Moles of solute"/"Volume of solution"$

Explanation:

$Molarity = \frac{95.5 \cdot g}{101.10 \cdot g \cdot m o l^{- 1}} \times \frac{1}{750 \times 10^{- 3} L}$ $"Molarity"=(95.5*g)/(101.10*g*mol^-1)xx1/(750xx10^-3L)$ $=$ $=$

$? ? \cdot m o l \cdot L^{- 1}$ $??*mol*L^-1$

Science

Math

Humanities

... and beyond

How do you calculate the molarity of a solution prepared by dissolving 95.5 grams of $K N O_{3}$ $KNO_3$ in enough water to make 750 mL of solution?

1 Answer

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

How do you calculate the molarity of a solution prepared by dissolving 95.5 grams of KNO3KNO_3 in enough water to make 750 mL of solution?

1 Answer

Explanation:

Related questions

Impact of this question

How do you calculate the molarity of a solution prepared by dissolving 95.5 grams of $K N O_{3}$ $KNO_3$ in enough water to make 750 mL of solution?