Question

How do you complete the square to find the vertex for `y=x^2-3x+2`?

Answer 1

To complete the square half the coefficient of x, that is `-3/2`, then square it, that is `9/4`. Now add and subtract it to the expression as follows:

y=`x^2 -3x +9/4 -9/4 +2`

=`(x-3/2)^2 -1/4`. That is how 'complete the square' is done.

Vertex is `(3/2, -1/4)`